q=%28%E7%BE%8E%29%E5%B8%83%E6%8B%89%E5%BE%B7%E5%88%A9%C2%B7A.+%E4%BF%84%E8%8E%AB%E6%9E%97%28Bradley+A.+Ermeling%29%EF%BC%8C%28%E7%BE%8E%29%E5%90%89&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&curlibcode=BNZYTSG&searchWay0=marc&logical0=AND
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(美)布拉德利·A. 俄莫林(Bradley A. Ermeling),(美)吉